(a-b)^3 + (b-c)^3 + (c-a)^3 ?
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i think that this may be the answer not sure sorry
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let x=(a-b)³,y=(b-c)³ and z=(c-a)³
consider,x+y+z= (a-b) +(b-c) + (c-a) =0
==>x³+y³+Z3 =3xyz
That is (a-b)1 +(b-c)³ +(c-a)³ = 3(a-b)(b-c)(c-a)
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