Math, asked by juhee94singh, 1 year ago

(a-b)3+(b-c)3+(c-a)3
3(a-b) (b-c) (c-a)

Answers

Answered by ap9607040
0

Answer:

Step-by-step explanation:

let(a-b)=x

(b-c)=y

(c-a)=z

so,

atq

LHS=(a-b)^3+(b-c)^3+(c-a)^3

=x3+y3+z3

=3*xyz

=3*(A-B)*(B-C)*(C-A)=RHS

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