(a-b)3+(b-c)3+(c-a)3
3(a-b) (b-c) (c-a)
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0
Answer:
Step-by-step explanation:
let(a-b)=x
(b-c)=y
(c-a)=z
so,
atq
LHS=(a-b)^3+(b-c)^3+(c-a)^3
=x3+y3+z3
=3*xyz
=3*(A-B)*(B-C)*(C-A)=RHS
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