Question

(a-b)³+(b-c)³+(c-a)³​

Answer 1

Answer:

1

Step-by-step explanation:

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Answer 2

Answer:

if a + b + c = 0 , then a³+b³+c³ = 3abc

here (a-b) = a

(b-c) = b

(c-a) = c

so a+b+c = (a-b+b-c+c-a) = 0

therefore, a³+b³+c³ = 3abc

(a-b)³+(b-c)³+(c-a)³ = 3abc

= 3(a-b)(b-c)(c-a)