Question

(a-b) ^3 +(b-c) ^3 +(c-a) ^3 =
​

Answer 1

Answer:

-3a²b+3ab²-3b²c +3bc²-3ac² +3a²c

(a - b) ³:a³-3a²b+3ab² - 6³

=a³-3a²b +3ab²-b³ + (b-c)³ + (c-a)

(b-c) ³: b³ − 3b²c +3bc² - c³

= a³ - 3a²b +3ab² - b³ + b³3b²c +3bc² - c³ + (c -a)

(c-a) ³: c³ - 3ac² +3a²c-a³

=a³ - 3a²b +3ab² - b³ + b3³-3b²c +: = +3bc²-c³ + c³ -a)