Math, asked by Thejasswini, 1 year ago

a-b=5.
a^3-b^3/a^2+ab+b^2=
125/a^2+ab+b^2.
then find the value of ab

Answers

Answered by praveen96
3
a³ + b³ = (a + b) (a² - ab + b²)
= 10 (58 - ab)
But (a + b)² = a² + 2ab + b² = 58+2ab
also (a+b)2=10² = 100 since a+b=10
58+2ab=100
=> 2ab =100-58=42
=> ab = 21
=>a³ + b³ = (a + b) (a² - ab + b²)
= 10 (58 - ab)
=10*(58 - 21) = 370

Thejasswini: I can't understand
Thejasswini: it's a-b
Thejasswini: but how you got a+b
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