Question

A
B
5 In the adjoining figure, AD = BC
and BD = AC. Prove that:
ZADB = ZBCA
and ZDAB = ZCBA.
Hint. AABD ABAC (SSS)
D
C​

Answer 1

Answer:

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Answer 2

IN TRIANGLE ADB AND TRIANGLE BCA

• AD=BC (GIVEN)
• DB=CA (GIVEN)

ANGLE DAB = ANGLE ABC (ANGLEA OPPOSITE TO EQUAL SIDES ARE ALSO EQUAL)

SO, TRIANGLE ADB CONGRUENT TO TRIANGLE BCA (SAS)

SO ANGLE ADB = ANGLE BCA (CPCT)

ALSO ANGLE DAB = ANGLE CBA (CPCT)

HENCE, IT IS PROVED.

THAT TRIANGLE ABC =~ BAC (SSS).

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