Question

a-b=6 , ab=40 ,what is the solution for a^2+b^2 and (a+b)^2

Answer 1

✍✍HERE IS YOUR SOLUTION…⬇⬇

========================================

$\underline{SOLUTION}$ ➡

$\underline{Given ,}\\ \\ a - b = 6 \\ \\ ab =4 0 \\ \\ \\ \underline{To \: find :} \: \: (i)\: \: \boxed {a {}^{2} + b {}^{2}} \\ \\ (ii)\: \: \boxed{( a + b) {}^{2}}$
_______________________________

$\boxed{(i) }\: \: \: \: a {}^{2} + b {}^{2} \\ \\ = (a - b) {}^{2} + 2ab \\ \\ =( 6) {}^{2} + 2 \times 40 \\ \\ = 36 + 80 \\ \\ = 116$

__________________________________
$\boxed{(ii)} \: \: \: \: (a + b) {}^{2} \\ \\ = (a - b) {}^{2} + 4 ab \\ \\ = (6) {}^{2} + 4 \times 40 \\ \\ = 36 + 160 \\ \\ = 196$

__________________________________
$<marquee>$
✝✝…HOPE…IT…HELPS…YOU…✝✝