Math, asked by sanjay867, 1 year ago

A×B=6x^2+4x-1 . Find the value of a

manchalaraghupathi: Where is the variable a in the queation

Answers

Answered by adeshrajputtirwa

0

Answer:

Step-by-step explanation:

A×B=6x^2+4x-1

A×B=[-4+-√4^2-4×6×(-1)]/2×6

=[-4+-√16+24]/12

=[-4+-√40]/12

=[-4+-2√10]/12

=[-2+-√10]/6

Cimparing

A=[-2+√10]/6 &

B=[-2-√10]/6

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