Question

a+b=8,c*d=9,a*c=21,b-d=5,then value of a,b,c,d, is????

Answer 1

Answer:

Step-by-step explanation:

Here's Ans:

Answer 2

Given:

$\bold{a+b=8}\\\bold{c\times d=9}\\\bold{a\times c=21}\\\bold{b-d=5}$

To find:

a, b, c, d = ?

Solution:

$\bold{a+b=8}....(i)\\\bold{c\times d=9}....(ii)\\\bold{a\times c=21}....(iii)\\\bold{b-d=5}....(iv)$

Solve the equation (i) and put the value into the equation (iii):

$\to a+b=8\\\\\to a=8-b$

equation (iii):

$\to a\times c =21$

$\to (8-b) \times c =21\\\\\to 8c-bc=21.....(a)$

Solve the equation (iv) and put the value into the equation (ii):

$\to b-d=5\\\\\to d= b-5$

equation (ii):

$\to c\times d=9\\\\\to c\times (b-5)=9\\\\\to bc-5c=9.....(b)$

Solve the equation (a) and but the value in the equation (b):

Equation:

$\to 8c-bc=21\\\\\to bc= 8c-21$

put the value of bc into the equation (b):

$\to 8c-21-5c=9\\\\\to 8c-5c=9+21\\\\\to 3c=30\\\\\to c= \frac{30}{3} \\\\\to c= 10$

put the value of c in equation (ii) and (iii):

equation (ii):

$\to c\times d=9\\\\\to 10 \times d=9\\\\\to d= \frac{9}{10}\\\\\to d= 0.9$

equation (iii):

$\to a\times c=21\\\\\to a=\frac{21}{c}\\\\\to a=\frac{21}{10}\\\\\to a= 2.1$

put the value of "a" into the equation (i):

$\to a+b=8\\\\\to 2.1 +b=8\\\\\to b=8-2.1\\\\\to b=5.9$

The final value of a, b, c, d is: 2.1, 5.9, 10, 0.9