A two digit number is 4 times the sum of its digits. If 18 is added to the number, the digits are reversed. Find the number.
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Step-by-step explanation:
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Step-by-step explanation:
let the digit in the unit place be x
then the digit in the tens place =4-x
* required number = 10(4-x)+x
=40-10x+x
=40-9x
then the number after interchanging digits = 10x+(4-x)10x+4-x
=10x+4
according to question
40-9x+18=10x+4
58-4x=10x+4
6x=54x=54/6
x=9
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