Question

(a/b)=(9/7)^-3 ÷ (3/7)^1 , then find the value of (a/b)^2​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$\frac{a}{b} = {( \frac{9}{7} )}^{ - 3} \div {( \frac{3}{7} )}^{1} \\ \frac{a}{b} = {( \frac{7}{9}) }^{3} \times \frac{3}{7} \\ \frac{a}{b} = \frac{ {7}^{3} }{ {3}^{6} } \times \frac{3}{7} \\ \frac{a}{b} = \frac{ {7}^{3 - 1} }{ {3}^{6 - 1} } \\ \frac{a}{b} = \frac{ {7}^{2} }{ {3}^{5} }$

(a/b)² = (7²/3⁵)²

$= {( \frac{ {7}^{2} }{ {3}^{5} }) }^{2} \\ = \frac{ {7}^{4} }{ {3}^{10} }$

Hope you get your answer