Question

A+B=90° so sec²A+sec²B=sec²A.sec²B prove that

Answer 1

sec^2A + sec^2B= sec^2Asec^2B

sec^2(90-B) + sec^2B

cosec^2B + sec^2B

1/sin^2B + 1/cos^2B

sin^2B+cos^2B/sin^2Bcos^2B

1/ssin^2Bcos^2B

sec^2Bcosec^2B

Hope you understood!!!