Question

(a-b)(a^2+b^2+ab)-(a+b)(a^2+b^2-ab)

Answer 1

Answer:

-2b^3

Step-by-step explanation:

(a-b)(a^2+b^2+ab)=a^3+ab^2+a^2b-ba^2-b^3-ab^2=a^3-b^3 take this as 1

(a+b)(a^2+b^2-ab)=a^3+ab^2-a^2b+ba^2+b^3-ab^2=a^3+b^3 take this as 2

from 1 and 2 we get

(a-b)(a^2+b^2+ab)-(a+b)(a^2+b^2-ab)=a^3-b^3-(a^3+b^3)

multiply the minus sign into the brackets

=a^3-b^3-a^3-b^3 = -2b^3

Answer 2

Answer:

0

Step-by-step explanation:

(a-b) (a²+b²+ab) -(a+b) (a²+b²-ab)

a(a²+b²+ab) -b(a²+b²+ab) -a(a²+b²-ab) -b(a²+b²-ab)

a³+ ab²+ a²b - a²b- b³- ab² - a³- ab²+ a²b - a²b - b³ +ab²

According to cancellation law( +a³and -a³  gets cancelled)

(+ab²and -ab²  gets cancelled)

(+a²b and -a²b  gets cancelled)

(+b³and -b³  gets cancelled)

(-ab²and +ab²  gets cancelled)

(+a²band -a²b  gets cancelled)

at last after cancelling all these you get the answer as 0