Math, asked by subhasishlcd, 9 months ago

(a+b)(a+b)(a+b)+(a-b)(a-b)(a-b))

Answers

Answered by spiderman2019
22

Answer:

2a(a²+3b²)

Step-by-step explanation:

(a+b)(a+b)(a+b)+(a-b)(a-b)(a-b)

= (a+b)³ + (a-b)³

= a³ + b³ + 3a²b + 3ab²+ a³ - b³ - 3a²b+ 3ab²

= 2a³+6ab² = 2a(a²+3b²)

Answered by EthicalElite
7

•(a+b)(a+b)(a+b)+(a-b)(a-b)(a-b)

:-(a+b)³+(a-b)³

:-a³+b³+3a²b+3ab²+a³-b³-3a²b+3ab²

:-2a³+6ab²

:-2a(a²+3b²)

Hope it helps you,

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