(a-b)(a-b)-(a+b)(a-b) is equal to:
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Answered by
43
=(a^2+b^2-2ab) - ( a^2-b^2)
= a^2+b^2-2ab-a^2+b^2
= 2b^2-2ab
= a^2+b^2-2ab-a^2+b^2
= 2b^2-2ab
Answered by
58
@
(a-b)(a-b)-(a+b)(a-b)
→ Here we have (a-b)(a-b) = (a-b)²
& (a+b)(a-b) = a²-b²
→(a-b)² - (a² - b²)
→ a² + b² - 2ab - a² + b²
→ 2b² -2ab
Hence (a-b)(a-b)-(a+b)(a-b) = -2ab
@:-)
(a-b)(a-b)-(a+b)(a-b)
→ Here we have (a-b)(a-b) = (a-b)²
& (a+b)(a-b) = a²-b²
→(a-b)² - (a² - b²)
→ a² + b² - 2ab - a² + b²
→ 2b² -2ab
Hence (a-b)(a-b)-(a+b)(a-b) = -2ab
@:-)
omkaryadav1:
wrong answer i
hmm bro so what is the correct answer ?
answer is 2b-2ab
answer is 2b2-2ab
this correct answer
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