Math, asked by ravirajmeena4321, 9 months ago

(a - b) (a+b) + (b - c) (b+c) + (с – а) (c+a) = 0​

Answers

Answered by priyaMajumdar
4

Answer:

(a-b)(a+b)+)(b-c)(b+c)+(c-a)(c+a) =0

a²-b²+b²-c²+c²-a²=0

0=0 (prove)

Step-by-step explanation:

we know that....

a²-b²=(a-b)(a+b)

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