(a - b) (a+b) + (b - c) (b+c) + (с – а) (c+a) = 0
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Answer:
(a-b)(a+b)+)(b-c)(b+c)+(c-a)(c+a) =0
a²-b²+b²-c²+c²-a²=0
0=0 (prove)
Step-by-step explanation:
we know that....
a²-b²=(a-b)(a+b)
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