(a-b)(a+b)+(b-c)(b+c)+(c-a)=0
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I think, your question should be like this,
(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)
On solving this, we can get answer as 0.
➡ (a-b)+(a-b)+(b-c)(b+c)+(c-a)(c+a)
➡ ( a²-b² ) + ( b² - c² ) + ( c² - a² )
➡ a² - b² + b² - c² + c² - a²
➡ 0
Hope it will help you !!!
(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)
On solving this, we can get answer as 0.
➡ (a-b)+(a-b)+(b-c)(b+c)+(c-a)(c+a)
➡ ( a²-b² ) + ( b² - c² ) + ( c² - a² )
➡ a² - b² + b² - c² + c² - a²
➡ 0
Hope it will help you !!!
ria58:
i have
can u explain it pls
is the answer correct?
yaa, sure
sure checked
i got it to
apply the formula, (a+b) (a-b) = a² - b²
☺tq
before there asking 0
before there asking 0??? what?
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