Solve This Trignometry Question Then I will Mark Your Answer As Brainliest?
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sec^6tetha-tan^6tetha=1+3tan^2tetha+3tan^4tetha
sec^6tetha=1+3tan^2tetha+3tan^4tetha+tan^6tetha...
PROOF:-
sec6 θ = (sec2 θ)3 = (1 + tan2 θ)3
= (1)3 + (tan2 θ)3 + 3 × 1 × tan2 θ (1 + tan2 θ)
= 1 + tan6 θ + 3 tan2 θ sec2 θ
sec^6tetha-tan^6tetha=1+3tan^2tetha+3tan^4tetha
sec^6tetha=1+3tan^2tetha+3tan^4tetha+tan^6tetha...
PROOF:-
sec6 θ = (sec2 θ)3 = (1 + tan2 θ)3
= (1)3 + (tan2 θ)3 + 3 × 1 × tan2 θ (1 + tan2 θ)
= 1 + tan6 θ + 3 tan2 θ sec2 θ
Triyan:
the identity i used is 1+tan2tetha=sec2tetha
Give me full solution
that is the solution
i just sent tan^6tetha the other side
it is simple just see and understand bro! that is 1 cube so it is 1
and i expanded (a+b)^3
No you give me your solution in notebook then i will mark you brainliest
Sorry bro i am currently traveling.. i don't have notes
and last expand sec^2tetha as 1+tan^2tetha
Ok broo but i will give you thankss
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