Question

(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)​

Answer 1

Step-by-step explanation:

$(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)$

$a^{2}-b^{2}+\left(b+c\right)\left(b-c\right)+\left(c+a\right)\left(c-a\right)$

$a^{2}-b^{2}+b^{2}-c^{2}+\left(c+a\right)\left(c-a\right)$

$a^{2}-c^{2}+\left(c+a\right)\left(c-a\right)$

$a^{2}-c^{2}+c^{2}-a^{2}$

$a^{2}-a^{2}$

$0$

i hope it helps

Answer 2

question:-

simplify : (a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)

solution:-

0

let's find out:-

• => (a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)

• => a(a-b) b(a-b) + b(b-c) c(b-c) + c(c-a) a(c-a)

• =>a²-ab+ab-b²+b²-bc+bc-c²+c²-ac+ac-a²

• combine all like terms

• =>a²-a²+b²-b²+c²-c²-ab+ab-bc+bc-ac+ac

• so, here all like terms will cut and We will get 0

=> 0

hence the ANSWER is 0

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>>> learn more :-

simplify:-

1. (x²-5) (x+5) +25
2. (a²+5) (b³+3) +5
3. (t+s²) (t²-s)

let's find out!!!

1. (x²-5) (x+5) + 25

=> x²(x+5) -5(x+5) + 25

=> x³+5x² - 5x-25 + 25

=> x³ + 5x² - 5x

2. (a²+5) (b³+3) + 5

=> a²(b³+3) 5(b³+3) +5

=> a²b³+ 3a² + 5b³+15+15

=> a²b²+3a²+5b³ + 30

3. (t+s²) (t²-s)

=> t(t²-s) s²(t²-s)

=> t³- ts -t²s² -s³

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