Math, asked by AB680443, 4 months ago

(a + b)(a - b) + (b + c)(b -c)+(c + a)(c-a)​

Answers

Answered by amankumaraman11
0

 \small \rm(a + b)(a - b) + (b + c)(b -c)+(c + a)(c-a) \\   \\ \rm{ {a}^{2}  -  {b}^{2}  +  {b}^{2} -  {c}^{2}   +  {c}^{2} -  {a}^{2}  } =  \red0

Answered by hemantabaruah23
0

Step-by-step explanation:

(a + b)(a - b) + (b + c)(b -c)+(c + a)(c-a)

=> a²-b² + b²-c² + c²-a²

=> 0

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