Question

(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)​

Answer 1

Step-by-step explanation:

a^2-b^2+b^2-c^2+c^2-a^2

= 0

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Answer 2

$= ( {a}^{2} - {b}^{2} ) + ( {b}^{2} - {c}^{2} ) + ( {c}^{2} - {a}^{2} )$

$= ( {a }^{2} - {a}^{2} ) + ( {b}^{2} - {b}^{2} ) + ( {c}^{2} - {c}^{2} )$

$= 0$

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