|a+b|=|a|+|b| then the angle between the vectors a and b is
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As per the question :-
=> √(a² + b² + 2ab cos@) = a + b
=> a² + b² + 2ab cos@ = a² + b² + 2ab
=> cos@ = 1
=> @ = 0
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Answer:
In this case the angle between them will be 0°
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