A body is projected vertically up with velocity 98m/s
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Assuming the question is:
A body is projected vertically up with a velocity 98m/s. After 2sec, if the acceleration disappears, what is the velocity of the body at the end of 3sec??
From the question, it is interpreted that the body is projected with initial velocity of 98 m/s (on earth) and no further propulsion is applied, making it a vertical projectile.
After two seconds, the velocity is reduced to:
v1=v0-at=98-2*9.8=78.4.
If g is removed (by whatever means imaginable), then the body will continue at constant velocity v1=78.4 m/s upwards after 2 seconds until g is reinstated. (review Newton's first law).
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