a-b+ab,b+c-bc and c-a-ac is
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3
Answer:
a -b+ab+(b+c-bc )+(c-a-ac)
2c+ab -bc -ac
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0
Answer:
=(a−b+ab)+(b−c−bc)+(c−a−ac)
=a−b+ab+b+c−bc+c−a−ac
Rearranging and collecting like terms,
=a−a−b+b+c+c+ab−bc−ac
=2c+ab−ac−bc
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