Question

The co-ordination number and the oxidation state of the element 'M' in the complex [M(en)2(C2O4)] NO2 (where, en is ethane-1,2-diamine) are respectively
a) 6 and 2
b) 4 and 2
c) 6 and 3
d) 4 and 3​

Answer 1

Answer:

Hence overall the coordination number of the element E is 4+2=6.

(counter ion) carries −1charge.

So, x+(2×0)+(−2)+(−1)=0

x−2−1=0

x=+3

Hence,option B is correct.

Answer 2

Answer:

c) 6 and 3

Explanation:

Let the oxidation state of metal 'M' be x

For complex, [M(en)₂ (C₂O₄)]NO₂

x + 0 − 2 = +1

x = +3

Also, ethylenediamine and C₂O²₄− both are bidentate ligands.Thus, coordination number will be '6'.

Hope it helps.Thanks.