Math, asked by Anonymous, 1 year ago

(a+b+ab)+(b-c+bc)+(c+a+ac)

Answers

Answered by master55538

1

Answer:

2(a+b)+ab+bc+ac is th answer

Answered by konrad509

1

$(a+b+ab)+(b-c+bc)+(c+a+ac)=2a+2b+ab+bc+ac$

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