Question

the area area of a right-angled traingle whose base is 1.2m and hypotenuse 3.7m.

Answer 1

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Given, length of base = 1.2 m

Hypotenuse = 3.7 m

Now, APPLYING PYTHAGORAS THEOREM,

Hypotenuse ^2 = Altitude ^2 + Base^2

=> 13.69 = Altitude ^2 + 1.44

=> Altitude ^2 = 12.25

=> Altitude = 3.5

We know that, Area of a right angled triangle

= 1/2 × base × altitude

= 1/2 × 1.2 × 3.5

= 2.5 m ^2

$<marquee >HOPE IT HELPS UH! </marquee >$

Answer 2

base is 1.2 m = 120cm
hypotenus is 3.7m = 370cm
by pythagoras theorem
${p}^{2} = {h}^{2} - {b}^{2}$
$p = \sqrt{ {120}^{2} + {370}^{2} }$
p=350cm
p=3.5m
area=
$= > 1 \div 2(1.2 + 3.5)$
=2.35sq m