Question

a, b and c are positive integers a : b =3 :8 b : c = 6 : 11.
a : b = 3 : 8 and b : c = 6 : 11
Work out the smallest posible value of a+b+c

Answer 1

Step-by-step explanation:

a/b = 3/8

b/c = 6 /11

We have b as common in both the ratios

In order to make b equal values multiply

a/b with 3 and b/c with 4

Now

a/b = 9/ 24

b/c = 24/44

Clearly

a = 9

b = 24

c = 44

We cannot simply the ratio future

Therefore a + b + c = 9 + 24 + 44

= 77