Question

A, B and C are the angles of a triangle prove that sec b + c upon 2 equal to Cos A upon 2




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Answer 1

Answer :

since A + B+ C = 180°

see the picture for the process .

Answer 2

SOLUTION

As we know that the sum of angles of the triangle is equal to 180°.

A + B + C = 180°

C = 180 - (A + B) ..... DIVIDE BOTH SIDE BY 2

C/2 = 90° - (A + B) /2

APPLY Cos OPERATOR ON BOTH SIDE.

Cos(C/2) = Cos(90°- {A+B}/2)

And we know that Cos(90 - A) = SinA

Cos(C/2) = Sin(A+B/2)

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