Question

A b and c are the lengths of three sides of triangle abc. If a b and c are related by a square +bsquare+ c square-ab-bc-ac=0 then value of sin square a+ sin square b+ sin square c is

Answer 1

Answer:

Step-by-step explanation:

a2+b2+c2=ab+bc+ca

⇒2(a2+b2+c2)=2(ab+bc+ca)

⇒2a2+2b2+2c2=2ab+2bc+2ca

⇒a2+a2+b2+b2+c2+c2=2ab+2bc+2ca

⇒(a2+b2−2ab)+(a2+c2−2ac)+(b2+c2−2bc)=0

⇒(a−b)2x+(b−c)2y+(c−a)2z=0

As x,y,z all are squares so they are all positive.

And their addition is zero only when all are zero.

So,

(a−b)2=0(1)

(b−c)2=0(2)

(a−c)2=0(3)

Solving the above three equations you will get,

a=b=c

Hence the triangle is equilateral.

Brainliest plzz

Answer 2

Answer:

it is equilateral triangle