Question

A,B and C are three points on a circle such that the angles subtended by the chords AB and AC at centre O are 80 and 120 respectively determine angle BAC

Answer 1

Given : AB and AC subtend 80° and 120° at centre.

⇒ ∠AOB = 80° and ∠BOC = 120°

Now ∠AOB + ∠BOC + ∠AOC = 360°
⇒ 80° + 120° + ∠AOC = 360°
⇒ ∠AOC = 360° – 200° = 160°

We know that angle subtended by the arc at the centre is double the angle subtended by it at any point on the circle.


Hence In ∆ABC
∠A = 60°, ∠B = 80° and ∠C = 40°
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Answer 2

Answer:

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