Question

A, b and c can all together do piece of work in 20 days, in which b takes twice as long as a and c together do the work and c takes twice as long as a and b together take to do the work. in how many days b can alone do the work? solution

Answer 1

(A+C) in x days so B completes in 2x days then

(1/x) + (1/2x) = 1/20

solve, x = 30, so B 2x =60days