A, b and c can complete a job working individually in 10, 20 and 60 days respectively. if they work together, in how many days will they complete the work?
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Days taken by each to do a work:-
by A=10 days
by B=20 days
by C=60 days
Days taken by each to do work in 1 day:-
by A= 1/10
by B=1/20
by C=1/60
Total work done by togther in 1 day
A+B+C = 1/10+1/20+1/60
A+B+C= 6/60 + 3/60+1/60
A+B+C=10/60
A+B+C=1/6 work
1/6 work is done by A,B,C together in 1 day
Work left= Total work-work done
1-1/6
6/6-1/6
5/6 Work left
1/6 work done in 1 day
5/6 work done in=5 days
Total days=1+5 =6days
So,
A,B,C can do together in 6 days.
HOPE IT HELPS YOU!
by A=10 days
by B=20 days
by C=60 days
Days taken by each to do work in 1 day:-
by A= 1/10
by B=1/20
by C=1/60
Total work done by togther in 1 day
A+B+C = 1/10+1/20+1/60
A+B+C= 6/60 + 3/60+1/60
A+B+C=10/60
A+B+C=1/6 work
1/6 work is done by A,B,C together in 1 day
Work left= Total work-work done
1-1/6
6/6-1/6
5/6 Work left
1/6 work done in 1 day
5/6 work done in=5 days
Total days=1+5 =6days
So,
A,B,C can do together in 6 days.
HOPE IT HELPS YOU!
prem144:
HLO!
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