A. B and C can complete a piece of work in 10, 15 and 18 days respectively. In how many days
would all of them complete the same work working together?
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Answer:
First we take LCM of 10,15,18
LCM =90
so total work is 90 units
A work done in 1 day =90/10
=9 units
B work done in 1 day = 90/15
=6 units
similarly ,C work done in 1 day =90/18
=5units
so A,B,C work done in one 1 day=9+6+5=20 units
total work = 90units
work done by A,B,C together in =90/20
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