Question

A. B and C can complete a piece of work in 10, 15 and 18 days respectively. In how many days
would all of them complete the same work working together?​

Answer 1

Answer:

First we take LCM of 10,15,18

LCM =90

so total work is 90 units

A work done in 1 day =90/10

=9 units

B work done in 1 day = 90/15

=6 units

similarly ,C work done in 1 day =90/18

=5units

so A,B,C work done in one 1 day=9+6+5=20 units

total work = 90units

work done by A,B,C together in =90/20