Math, asked by poojareddy725, 1 year ago

. a, b and c can complete a piece of work in 8, 12 and 24 days respectively. a and c started working, and b joined them after one day. if c left 2 days before completion of the work, in how many days was the work finished? (a) days (b) days (c) days (d) days (e) days


AtomicBlonde: what's with the options, plz fix this

Answers

Answered by anandhome
0
a=8
b=11
c=22
so the total days in which the work will be completed be 41 days

Answered by sshibubs
0

Answer:

4 2/3 days

Step-by-step explanation:

take LCM for total work, so total work -24

then calculate efficiency,

A's efficiency-3

B's efficiency-2

C's efficiency-1

so first day: (A+C)= 4 work

last 2 day: (A+B)= (3+2)*2=10 work

therefore, 3 days 14 work completed, the remaining work is 10.

remaining work completed by (A+B+C)=6

so, 10/6= 1 4/6 = 1 2/3

so total days = 1+2+1 2/3 = 4 2/3 days

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