A bag contains 4 black and 6 red balls. find the probability of drawing one ball which is either black or red?
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total balls 4+6=10 balls
P (red ball)=6/10=3/5
P(black ball) =4/10=2/5
P (red ball)=6/10=3/5
P(black ball) =4/10=2/5
Answered by
4
I THINK IT'S
No. of black balls=4
No. of red balls=6
No. of total balls=10
Probability=1:10
HOPE THIS HELPS!!!!!!
No. of black balls=4
No. of red balls=6
No. of total balls=10
Probability=1:10
HOPE THIS HELPS!!!!!!
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