Question

A,B and C can complete a work in 9 days 15 days and 18 days if they work alone. they start the work together and after three days A leaves .How many more days do B and C require to complete the work

Answer 1

B and C takes
$2 \times \frac{5}{11}$
days to complete remaining work

Answer 2

Answer:

2.45 days or 27/11

Step-by-step explanation:

A 1 day work = 1/9

B 1 day work = 1/15

C 1 day work = 1/18

A B C together 1 day work = 1/9 + 1/15 + 1/18

= (10+6+5)/90

= 21/90

= 7/30

ABC together 3 day work = 3*7/30= 7/10

Remaining work = 1-7/10 = 3/10

B&C together 1day work = 1/15 +1/18

= (6+5)/90

= 11/90

11/90 work is done in 1 day

1 work is done in 1/(11/90) = 90/11

3/10 work will be done = (90/11)×(3/10)

= 27/11

= 2.45 days