Question

A, b and c can do a piece of work in 30, 20 and 10 days respectively. A is assisted by b on one day and by c on the next day, alternately. How long would the work take to finish?

Answer 1

hope this helps you....

Answer 2

$9\frac {3}{8}$ days Work will be Completed

Step-by-step explanation:

• First day A+B worked = 2+3 = 5 units

• Second Day A + C Worked = 2 + 6 = 8 units

• Third Day A + B Worked = 5 units

• In one cycle work is completed = 13 units

It will continue at last, work will finish in

$\frac {60}{13(8+5)}= 4\ cycle$

and 8 units of work is left.

Now, A will do with 'B' and they will complete 5 units.

• Remaining 3 units will be done by A and C in

• Total Time = 4 cycle $\times$ 2 = 8 days

A + B = 1 days

A + C = $\frac {3}{8}$ days

Thus, Total Time = 8 days + (A+B)'s days + (A+C)'s days

= $8 + 1 + \frac {3}{8}$

= $9\frac {3}{8}$ days