A,B and C can do a piece of work in 6,8 and 12 hours respectively. They started work together after 1 hour B left the work. In how much time will the remaining work be completed by A and C.
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Efficiency of A = 1/6 part of work per day
Efficiency of B = 1/8 part of work per day
Efficiency of C = 1/12 part of work per day
Combined efficiency of B and C = 1/8 + 1/12 = 5/24 th part of work per day
Part of work done by B and C in 2 days = 2*5/24 = 5/12 th part of work
Left over work = 1 - 5/12 = 7/12 th part
Combined efficiency of A and C = 1/6 + 1/12 = 1/4 th part of work per day
No of days taken in finishing 7/12 th part of work = 7/12*4 = 7/3 days
Total time taken = 2 + 7/3 = 13/3 = 4 days and 8 hrs
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