A, b and c can do a piece of work in 72, 48 and 36 days respectively. for first p/2 days, a & b work together and for next ((p+6))/3days all three worked together. remaining 125/3% of work is completed by d in 10 days. if c & d worked together for p day then, what portion of work will be remained?
Answers
Answered by
1
Answer:
I don't know if I have the this type at the end but I guess u should we all know that we have no da or anything like that but it doesn't mean that you
Answered by
0
Total work is given by L.C.M of 72, 48, 36
Total work = 144 units
Efficieny of A = 144/72 = 2 units/day
Efficieny of B = 144/48 = 3 units/day
Efficieny of C = 144/36 = 4 units/day
According to the given data,
2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100
3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54
p = 198/16.5
p = 12 days.
Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day
(C+D) in p days = (4 + 6) x 12 = 120 unit
Remained part of work = (144-120)/144 = 1/6.
Similar questions