A,B and C can do a work in 12,24 and 8 days respectively. They all work for one day. They C leaves the group. In how many days will A and B complete the rest of th work?
Answers
Answered by
61
A can do in 12 d.
in 1 day 1/12
B can do in 24 d.
in 1 day 1/24
C can do in 8 d.
in 1 day 1/8
one day work =
{1/12 + 1/24 + 1/8} LCM
in 1 day 1/12
B can do in 24 d.
in 1 day 1/24
C can do in 8 d.
in 1 day 1/8
one day work =
{1/12 + 1/24 + 1/8} LCM
Answered by
14
Step-by-step explanation:
A can do a work in 12 days
B can do a work in 24 days
C can do a work in 8 days
Let total work be 24 (LCM of 12, 24, 8)
Therefore,
A can do 2 work in 1 day
B can do 1 work in 1 day
C can do 3 work in 1 day
Total work done by A, B, C together in 1 day = 2+1+3 = 6
After C left, total work left = 24-6 = 18
Total work done by A and B together in 1 day = 2+1 = 3
Therefore, rest of the work can be done by A and B together in = 18/3 = 6 days
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