Question

A B and C can separately do a work in 26 3 days respectively working together how much time they required to do it if the work on them 960 how should the divide the money . explain and answer
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Answer 1

Answer:

Given : A can do a work in 2 days , So

A's work for one day = 12

And

B can do a work in 6 days , So

B's work for one day = 16

And

C can do a work in 3 days , So

C's work for one day = 13

Then ,

Work done in one day if A , B and C work together = 12 + 16 + 13 = 3 + 1 + 26 = 66

Therefore ,

Work done by A , B and C if they work together in 166 = 66 = 1 day ( Ans )

And

A's work for one day = 12 , B's work for one day = 16 and C's work for one day = 13 , So

A's share : B's share : C's share = 12: 16 : 13

Now we multiply each ratio by LCM of ( 2 , 3 and 6 ) = 6 , Then

A's share : B's share : C's share = 3 : 1 : 2

So,

A's share = 9603 +1 + 2× 3 = 9606× 3 = 160 × 3 = Rs. 480 ( Ans )

And

B's share = 9603 +1 + 2× 1 = 9606× 1 = 160 × 1 = Rs. 160 ( Ans )

And

C's share = 9603 +1 + 2× 2 = 9606× 2 = 160 × 2 = Rs. 320 ( Ans )

Hope this information will clear your doubts about Ratio and Proportion .