Math, asked by RAJIB9684, 1 year ago

A,b and c complete a piece of work in 24,6,12 days respectively.If they work together in how many days they will complete the same work

Answers

Answered by rahul20vaishnav
3

Answer:

Step-by-step explanation:

1/a+/1/b+1/c = 1/w

1/24 +1/6 + 1/12 =1/w

1+4+2/24=1/w

Total days for work is w =24/7

Answered by dhanasekartool
4

Answer:

7/24 (or) 3+3/7

Step-by-step explanation:

A’s 1 day’s work = 1/24

B’s 1 day’s work = 1/6

C’s 1 day’s work = 1/12

(A+B+C)’s 1 day’s work = 1/24+1/6+1/12 (*24)

= 24/24+24/6+24/12

= 1 + 4 + 2 / 24

= 7/24

=3+3/7

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