A,b and c complete a piece of work in 24,6,12 days respectively.If they work together in how many days they will complete the same work
Answers
Answered by
3
Answer:
Step-by-step explanation:
1/a+/1/b+1/c = 1/w
1/24 +1/6 + 1/12 =1/w
1+4+2/24=1/w
Total days for work is w =24/7
Answered by
4
Answer:
7/24 (or) 3+3/7
Step-by-step explanation:
A’s 1 day’s work = 1/24
B’s 1 day’s work = 1/6
C’s 1 day’s work = 1/12
(A+B+C)’s 1 day’s work = 1/24+1/6+1/12 (*24)
= 24/24+24/6+24/12
= 1 + 4 + 2 / 24
= 7/24
=3+3/7
Similar questions