Question

A,b and c individually can do a certain piece of work in 35,42 and 24 days resp. They started working together but after x' days a and c left the job and the remaining work is completed by b with 25% more efficiency. If the whole work is completed in 114/5 days then find the value of x.

Answer 1

Answer:

Step-by-step explanation:

One day's work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.

C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.

Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.

Remaining Work = 7/10, which was done by A,B and C in the initial number of days.

Number of days required for this initial work = 7 days.

Thus, the total numbers of days required = 4 + 7 = 11 days.

Hope it helps you....