Question

An electric bulb is rated 60w 240v calculate its resistance

Answer 1

Answer :-

$R = 960\Omega$

Given :-

P = 60 w

V = 240 v

To find :-

The value of R.

Solution:-

Resistance → The property of a material to resist the flow of electric current through it self is called resistance.

Its SI unit is ohm.

By using the relationship between voltage , power and resistance we have:-

$\huge \boxed{P = \dfrac{V^2}{R}}$

Put the given value,

→$60 = \dfrac{(240)^2}{R}$

→$60 = \dfrac{57,600}{R}$

→$R = \dfrac{57,600}{60}$

→$R = 960 \Omega$

hence,

The resistance of electric bulb is $960\Omega$

Answer 2

Questions—

An electric bulb is rated 60w & 240v. calculate its resistance?

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$\huge\sf\underline{Answer}$

$\bf\huge\boxed{960\:ohm}$

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Given—

Power (P) = 60 W

Potential Difference(V) = 240 V

R = ?

Solution —

As we know

P = V²/R

putting the given value

=> 60 = (240)²/R

=> R = (240)²/60

=>R = 240 × 4

=> R = 960 ohm

Therefore, the Resistance will be 960 ohm.

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