Question

A, B and C shared some stickers in the ratio of 3:1:4. After C gave 40% of her stickers to A and B, A had 90 more stickers than C and the number of B's stickers increased by 70%. How many stickers did C have at first?

Answer 1

let the total no. of stickers be x
no. of stickers A has = 3x/8
no. of stickers B has = x/8
no. of stickers C has = 4x/8
40% of 4x/8 = 40/100(4x/8) = x/5
total no. of stickers C has = 4x/8 - x/5 = 12x/40 = 3x/10
70% 0f x/8 = 70/100(x/8) = 7x/80
total no. of stickers B has = x/8 +7x/80 = 17x/80
no. of stickers A got from C = x/5 - 7x/80 = 9x/80
total no. of stickers A has = 3x/8 + 9x/80 = 39x/80
39x/80 = 3x/10 +90
15x/80 = 90
x = 480
no. of stickers C had at first = x/2 = 240