Question

A , B and C starts cycling around a circular path in the same direction at the same time.circumference of the path is 1980m. is the speed of A is 330m/min , speed of B is 198m/min and the speed of C is 220m/min and they start from the same point, then after what time interval they will be together at the starting point?

Answer 1

A will complete one round in 1980/330 = 6 min B will complete one round in 1980/198 = 10 min C will complete one round in 1980/220 = 9 min  
Now, let A, B and C meet after time t and they would have respectively completed, n1, n2 and n3 rounds and they would be be x distance away from the start point 
Hence, 330t = x + 1980n1198t = x + 1980n2220t = x + 1980n3 Substituting x from equation 1 into 2 and 3198t = 330t - 1980n1 + 1980n21980(n1-n2) = 132tt = 15(n1-n2) Also,  220t = 330t - 1980n1 + 1980n31980(n1-n3) = 110tSince t is same, and n1-n3 and n1-n2 can be any whole number, so we need to compute LCM of 15 and 18 which is 90
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Answer 2

Answer:

Step-by-step explanation:

A will complete one round in 1980/330 = 6 min B will complete one round in 1980/198 = 10 min C will complete one round in 1980/220 = 9 min  

Now, let A, B and C meet after time t and they would have respectively completed, n1, n2 and n3 rounds and they would be be x distance away from the start point 

Hence, 330t = x + 1980n1198t = x + 1980n2220t = x + 1980n3 Substituting x from equation 1 into 2 and 3198t = 330t - 1980n1 + 1980n21980(n1-n2) = 132tt = 15(n1-n2) Also,  220t = 330t - 1980n1 + 1980n31980(n1-n3) = 110tSince t is same, and n1-n3 and n1-n2 can be any whole number, so we need to compute LCM of 15 and 18 which is 90

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