Math, asked by rambaburouthu514, 4 days ago

· A, B and C together can complete a piece of work in 30 days. A takes twice as long as B takes twice as long as A and C together to com- plete the same work. The number of days C alone needs to complete the work is​

Answers

Answered by scharanjot46
0

Answer:

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Step-by-step explanation:

Let B & C together take x days

A will take 2x days

1/2x + 1/x = 1/90

45 + 90 = x

x = 135 days

2x = 270 days So A alone takes 270 days

Let A & C take x days

B takes 3x days

1/x + 1/3x = 1/90

90 + 30 = x

x = 120 days

3x = 360 days So B alone takes 360 days

Let C alone take x days

1/270 +1/360 +1/X = 1/90

x = 216 days C alone takes 216 days ANSWER

CHECK

1/216 + 1/270 +1/360 = 1/90

Answered by swapnaraju961gmail
0

answer :3x=360 dayd

Step-by-step explanation:

I hope you help

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