Question

√a/b =(b/a)^1-3x
Find x

Answer 1

given root under a/b =(b/a)^1-3x
As (a/b)^1/2=(b/a)^1-3x
Then (b/a)^-1/2 =(b/a)^1-3x
Then solve for x in
-1/2=1-3x
You get x =1/2

Answer 2

Answer:

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