Math, asked by Kushagg8214, 1 year ago

a/b+b/a= -1 then (a^3-b^3)=?

Answers

Answered by Anonymous
1

Answer:

0

Step-by-step explanation:

a/b+b/a=-1

a^2+b^2/ab=-1

a^2+b^2=-ab

a^2+b^2+ab=0

a^3-b^3=(a-b)(a^2+b^2+ab)

=(a-b)*0=0

Answered by sriram979
1

a/b+b/a=-1

a*2+b*2/ab=-1

a*2+b*2=-ab

a*2+b*2+ab=o

now (a+b)*2-ab=0

as we know (a-b)(a*2+b*2+ab=(a*3-b*3)

(a-b)0=a*3-b*3

a*3-b*3=0

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